I got some help from others in a different technical forum. I thought I would share my learnings.
Stephen Marsh wrote:
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Here are the RGB Luminosity (gray) values for eight key test colours
(Adobe RGB) -
White: 255 (0%)
Black: 0 (100%)
255 R: 76 (70%)
255 G: 150 (41%)
255 B: 28 (89%)
RGB C: 179 (30%)
RGB M: 105 (59%)
RGB Y: 227 (11%)
Notice those last three idealised CMY % values? 30 59 11 ...
Sounds a bit like 30r 59g 11b, which is close to Photoshop RGB Luminosity weighting (not precise though, just close). Strange how that worked out, very strange indeed! Coincidence, or something deeper? Anyway, enough of that!
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I then wrote:
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As you suggested (and what I should have done initially), I looked at CS3's help file.
>>Luminosity: Creates a result color with the hue and saturation of the base color and the luminance of the blend color. This mode creates the inverse effect of Color mode.<<
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So looking at Black and White, the luminance values are 0 and 255. In RGB, luminance of 0 is always black. So the underlying color does not matter. Similarly, luminance of 255 is always white, so the underlying color does not matter. Am I correct?
For other colors in between black and white, their luminance values will be between 0 and 255. Thus, the underlying color does show through and the underlying colors do appear to affect the luminosity. For example, Red in sRGB has a luminosity value of 54. Yet, when I use my file (mentioned at the top of my response) with Luminosity blend mode, the luminosity varies from the low 30s to high 30s.
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Dan Margulis then wrote
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The above summary is correct. It is not possible to have an RGB color (meaning, other than white) that is as light as 255r255g255b, because to introduce the color one or more of the channels would necessarily darken. Similarly there cannot be color that is as dark as 0r0g0b because adding the color would necessarily lighten one or more channels.
In LAB such colors can be made theoretically and there are several uses in retouching for them. If you convert the files described above to LAB without flattening, you will create such imaginary colors. Photoshop displays them as being neither very colorful nor absolutely light or dark, but rather a combination of both. If you then flatten and reconvert to RGB the LAB look will hold.
> For other colors in between black and white, their luminance values
> will be between 0 and 255. Thus, the underlying color does show
> through and the underlying colors do appear to affect the
> luminosity. For example, Red in sRGB has a luminosity value of 54.
> Yet, when I use my file (mentioned at the top of my response) with
> Luminosity blend mode, the luminosity varies from the low 30s to
> high 30s.
This is just an extension of the white/black situation. When what's being called for is near the edge of what's achievable then it is likely not possible to retain both color and luminosity, so there will be some compromise.
255r0g0b is an example. This is the reddest red that RGB can produce, and it occurs only at one specific luminosity. If the file becomes either lighter or darker some of the redness must be lost.
Consequently, Luminosity/Color modes whether in RGB or LAB are only truly reliable with subtle colors. They do not work well when painting with near-whites or near-blacks. When brighter colors, or near-whites or near-blacks are in play, RGB and LAB behave differently and either (or neither) may be the result that's wanted.
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Dan Margulis is the author of the following two books:
1)
Professional Photoshop: The Classic Guide to Color Correction (5th Edition)
and
2)
Photoshop LAB Color: The Canyon Conundrum and Other Adventures in the Most Powerful Colorspace
Note, the two above links are Amazon sponsored links.
I am posting this information so that a) others don't spend time and effort addressing my question when it has already been answered, and b) to help others who might be interested.